Question

A man is 4 times as old as his son. After 10 years he will be only twice as old as his son. Find their present age.

Answer 1

Solutions :-

Let the son's age be x
Father's age = 4x
After 10 years, Age of son = x + 10
Age of father = 4x + 10


According to the question,

=> 2(x + 10) = 4x + 10
=> 2x + 20 = 4x + 10
=> 2x - 4x = 10 - 20
=> - 2x = - 10
=> x = - 10/-2 = 5


Hence,
Age of son = x = 5 years
Age of father = 4x = 4 × 5 = 20 years

Answer 2

_______Heyy Buddy ❤________

_____Here's your Answer ________

Let the age of his son be x yrs.

=> Age of Father = 4x yrs.

Condition II,

After 10 years,

Age of Son = (x + 10) yrs.

Age of Father = (4x + 10)

A.T.Q.

(4x + 10) = 2( x + 10)

=> 4x + 10 = 2x + 20

=> 2x = 10

=> x = 5.

Therefore,

Age of son = 5 yrs

Age of Father = 4×5 = 20 yrs.
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