Question

A man is 4 times as old as his son. After 16 years he will be only twice as old as his son. Find their present ages?​

Answer 1

answer is 32 hope it helps

Answer 2

$\bf{\underline{Solution:-}}$

At present :

At present :Son age = 8 years

At present :Son age = 8 yearsFather age = 32 years

Step-by-step explanation:

At present:

Age of son = x years

His Father age = 4x years

After 16 years:

Age of son = (x+16) years

Father age = (4x+16) years

According to the problem given

$\rm 4x + 16 = 2(x + 16)$

$\rm 4x + 16 = 2x + 32$

$\rm 4x - 2x = 32 - 16$

$\rm 2x = 16$

$\rm x = 16/2$

$\rm x = 8$

$\bf{\underline{Hence:-}}$

• Present age of son = 8 years
• Present age of father = 4x = 4 × 8 = 32 years