Question

a man is 4 times as old as his son . after 16 years he will be only twice as old as gis son . find their present ages

Answer 1

Let the age of child be x then father be 4x
Hence after 16 years
4x+16=2(x+16)
4x+16=2x+32
2x=16
X=8
Hence child age is 8 years and fathers age will be 32 years respectively....

Answer 2

let the age of son be x
then, father's age will be 4x
ages after 16 yrs,
father's age= 4x+16
son's age = x + 16
according to the question,
2(x+16)=4x+16
2x+32=4x+16
2x-4x=-32+16
-2x=-16
x=-16/-2
x=8
their present ages,
son will be 8 years
father's age will be 4×8=32 yrs