A man is 4 times as old as his son.After 16 years he will be only twice as old as his son.find their ages
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rajprashant:
i m not understandi g
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let the son's age be x,then man's she is 4x
after sixteen years son's age is (x+16),then man's is 2(x+16),but it should also be (4x+16),so
ATP
4x+16=2(x+16)
=>4x+16=2x+32=>4x-2x=32-16=>2x=16=>x=16/2
=>x=8
so the son's age is 8 and the man's age is 32
after sixteen years son's age is (x+16),then man's is 2(x+16),but it should also be (4x+16),so
ATP
4x+16=2(x+16)
=>4x+16=2x+32=>4x-2x=32-16=>2x=16=>x=16/2
=>x=8
so the son's age is 8 and the man's age is 32
i m impressed
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