Math, asked by sjk5, 1 year ago

A man is 4 times as old as his son.fter 16 years will be only twice as old as his son.Find their present ages

Answers

Answered by Somesh111
2
Let son age be x then father age is 4x.
ACQ;
2(X+16)=4x+16
2x +32 =4x+16
- 2X= - 16
X=8
SON AGE = 8; FATHER AGE =32.
HOPE YOU BRAINLIST

Somesh111: please
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sjk5: i have put
sjk5: THANKS
sjk5: you are not too big
sjk5: i thought you will be 18 years
Somesh111: no just 14 and yours
sjk5: 13
sjk5: please tell me one more answer
Answered by GelageetKumar
1
A man is 4 times as old as his son.
so, let a man's son's age be =x
After 16 years will be only twice as old as his son.
so, After 16 years his age =2(x+4) =16 .
=2x +8 =16.
2x=16-8.
2x=8.
x=8/2.
x=8 .
Now, x=8
then, man's age =8×4=32
And son's age =4 years.
HOPE ITS HELP YOU BROTHER.
MARK ME AS BRAINLIEST.

sjk5: wrong
Somesh111: what wrong
GelageetKumar: How????
GelageetKumar: Is it wrong??
sjk5: no
sjk5: wrong
sjk5: the man age is 32
sjk5: son 8
GelageetKumar: Ok, then
GelageetKumar: If u mark as brainliest so, u cann't thanks
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