Question

A man is 4 times as old as his son.fter 16 years will be only twice as old as his son.Find their present ages

Answer 1

Let son age be x then father age is 4x.
ACQ;
2(X+16)=4x+16
2x +32 =4x+16
- 2X= - 16
X=8
SON AGE = 8; FATHER AGE =32.
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Answer 2

A man is 4 times as old as his son.
so, let a man's son's age be =x
After 16 years will be only twice as old as his son.
so, After 16 years his age =2(x+4) =16 .
=2x +8 =16.
2x=16-8.
2x=8.
x=8/2.
x=8 .
Now, x=8
then, man's age =8×4=32
And son's age =4 years.
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