Question

A man is 4 times as old as hos son. After 16 years he will be only twice as old as his son. Find their present ages

Answer 1

Step-by-step explanation:

let son's age be x

man's age 4x

After 16 years

son's age = (16+x)

man's age = 4x+16

Equation :

2(16+x) = (4x+16)

32 + 2x = 4x + 16

2x - 4x = 16 - 32

-2x = -16

2x = 16

x = 16/2

x = 8

present age of son = 8 years

present age of man = 4× 8 years = 32 years