Question

A man is 40 years old and his son is 14 years old. In how many years will the father be twice as old as his son? with formula please

Answer 1

Answer:

man's age = 40(x)

son's age = 14(y)

(x+a) = 2 (y+a)

40+a = 2(14+a)

40+a = 28+2a

40-28 = a

12 = a

after 12 years, his son will be of 26 and man will be of 52, that is,twice

Step-by-step explanation: