Question

A man is 45m bend the bus, when the bus start accelerating from rest with acceleration 2.5m/s2. with what minimum velocity should the man start running to catch the bus?

Answer 1

Let man will catch the bus after 't' sec . So he will cover distance ut. Similarly distance travelled by the bus will be 12at2. For the given condition u t=45+12a t2=45+1.25 t2 [As a=2.5m/s2] Þ u=45t+1.25 t To find the minimum value of u dudt=0 so we get t=6secthen, u=456+1.25×6=7.5+7.5=15m/s