A man is 4times as old as his son. After 20years, he will be twice as old as his son at that time. Find their present age
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this is how you solve it : et x be the age of his son now, then the age of the father is 4x.
In 20 years,
The son's age = x + 20
The father's age = 4x + 20
As in 20 years the father will be twice as old as his son, we can set up an equation:
4x + 20 = 2(x + 20)
Solving the equation for x, we have
4x + 20 = 2x + 40
2x = 20
x = 10
So the age of his son now is 10, and the age of the the father now is 40
In 20 years,
The son's age = x + 20
The father's age = 4x + 20
As in 20 years the father will be twice as old as his son, we can set up an equation:
4x + 20 = 2(x + 20)
Solving the equation for x, we have
4x + 20 = 2x + 40
2x = 20
x = 10
So the age of his son now is 10, and the age of the the father now is 40
Answered by
1
Age of son is 10 years and age of father is 40 years.
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