A man is 7 times as old as his son now.4 years later, he will be 4 times as old as his son. find their present age
plzzzzzz guys help me
karan5116:
hi
Hi
Age of father b x then son's age will be y as per question x is equal to 7 y then X + 4 is equal to Y + 7 into x now solve it putting x is equal to 7 y
sorry it is a I wanted to say that then X + 4 is equal to Y + 7 into 4
Answers
Answered by
3
Let the age of his son be x years
Therefore,
Son's age = x
Man's age = 7x
After 4 years...
Son's age = x+4
Man's age = 7x + 4
ATQ...
=> 7x + 4 = 4(x + 4)
=> 7x + 4 = 4x + 16
=> 3x = 12
=> x = 4
Therefore,
Present age of son = 4 years
&
Present age of man = 7 × 4 = 28 years....
hope it helps...✌✌
Therefore,
Son's age = x
Man's age = 7x
After 4 years...
Son's age = x+4
Man's age = 7x + 4
ATQ...
=> 7x + 4 = 4(x + 4)
=> 7x + 4 = 4x + 16
=> 3x = 12
=> x = 4
Therefore,
Present age of son = 4 years
&
Present age of man = 7 × 4 = 28 years....
hope it helps...✌✌
thanks ❤️☺️❤️☺️
wlcm...☺
☺️❤️☺️❤️☺️
Similar questions