A man is at a certain distance from a cliff and he fires a gun and hears an echo after 1.5 seconds then he moves 437.5 away from the cliff and then now he hears the echo after 4 seconds.
find the speed of the sound.
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Answers
Answer:
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Explanation:
Let the distance of the cliff from the initial position of the man be d m.
So, the distance traveled by sound in 3 sec=2d m
So, speed of sound, S=
Time
Distance
S=
3
2d
.....(i)
On moving closer to the cliff by a distance of 82.5 m, the distance=2(d−82.5) m
So,
S=
t
d
S=
2.5
2(d−82.5)
=
2.5
2d−2×82.5
.....(ii)
Therefore form equation (i) and (ii)
3
2d
=
2.5
2d−2×82.5
5d=6d−495
d=495 m
Thus it is the distance of the cliff from the initial position of the man.
Now,
S=
3
2×495
=330 m/s
Answer:
A man standing in front of a vertical cliff fires a gun. He hears the echo after 3 s. On moving closer to the cliff by 82.5 m, he fires again and hears the echo after 2.5 s. Find: (i) the distance of the cliff from the initial position of the man and (ii) the speed of sound.
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