Question

A man is four times as old as his son and sum of their ages 40 years find their present ages

Answer 1

Answer:

Solution:

Man is four times as old as his son.

Present ages= 40(in sum)

Dividing their ages =40/4

Therefore the age of the son is 10 and his father is 50.

Hope it helps❤️

Answer 2

Answer:

your answer is in the attachment

$<marquee> just say thanks <marquee>$