Question

A man is four years older than his wife and 5 times as old as his son. When the son was born, the age of the wife is six-seventh that of her husband’s age. Find the age of his wife.

Answer 1

Answer:

I hope it will be helpful to you

Answer 2

Answer :-

Let us assume that, wife present age is x years old.

so,

→ Man age = (x + 4) years .

→ Son age = (x+4)/5 years .

now,

→ wife age when son was born = x - (x + 4)/5 = (5x - x - 4)/5 = (4x - 4)/5 years .

→ man age when son was born = (x + 4) - (x + 4)/5 = (4x + 16)/5

A/q,

→ wife age = (6/7) husband age

→ (4x - 4)/5 = (6/7)[(4x + 16)/5]

→ 7(4x - 4) = 6(4x + 16)

→ 28x - 28 = 24x + 96

→ 28x - 24x = 96 + 28

→ 4x = 124

→ x = 31 years (Ans.)

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