Question

a man is hanging from the free end of a massless rope of length 40m the mass of the man is 20 kg and the maximum tension that the rope bears in 300N. then starting from thr rest the minimum time in which the man can reach the other end of the rope is

Answer 1

Answer: Min. Time taken is 4sec

Explanation:

Answer 2

Answer:

Time t=4 seconds.

Explanation:

Using the formulae of tension we get that tension T - mg = ma, since for the mass tension will be more than its own weight.

300 - 20*10=20a.

On solving we will get the value of a to be 100/20 = 5 m/s^2.

Now, using Newtons second law of motion we will get distance S=ut +1/2at^2.

Since, u = 0m/s so on substituting the values from the question we will get the value of t^2 to be equal to 80/5 = 16 which on solving we will get time t = 4 seconds.