a man is moving with the acceleration of 1m/sec² from rest
Find the distance traveled by the man is 5th second
Answers
Answered by
0
by fouth equatin of mothion
snth = u+a/2 (2n-1)
s5th=0.5+1/2 (2×5-1)
=9.5/2=4.75m
snth = u+a/2 (2n-1)
s5th=0.5+1/2 (2×5-1)
=9.5/2=4.75m
Similar questions