A man is running to catch a bus standing at the bus stop with a uniform speed of 4m/s. When he is 15m
behind the bus, bus starts with a uniform acceleration 0.5 m/s. In how much time, the man catch the
bus?
(a) 4s
(b) 6s
(C) 10s
(d) He cannot catch the bus.
Answers
Answered by
0
Answer:
you can find the answer by the rule of time equal to distance upon speed
Answered by
1
Answer: B
Explanation: accel of man wrt to bus = -0.5m/sec²
s=ut+1/2at²
15=4t-1/4 t²
t²-16t+60=0
by sridharacharya method
t=(16±√256-240)/2
t=(16±4)/2
t=6 or 10 sec but 10 sec is rejected
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