Question

A man is seven times as old as his son.Two years ago, the man was thirteen times as old as his son . Find their present ages

Answer 1

Let son's age be x years
Man's age= 7x years
Two years ago,
Son's age=x-2
Man's age= 7x-2
7x-2=13(x-2)
7x-2=13x-26
6x=24
x=4
Son's age= 4 years
Man's age= 7*4 = 28 years