Question

A man is standing on a weighing machine placed in a lift. When stationary, his weight is recorded as 40 kg. If the lift is accelerated upwards with an acceleration of 2 m/s
2
, the weight recorded in the machine will be: (g = 10 m/s
2
)

Answer 1

Answer:

480 kg

Explanation:

Reaction on the person will be,

R=m(g+a)

=40(10+2)

=480kg

Answer 2

Answer: 48 Kg

⇒Mass of the man "m" = 40 Kg

⇒Acceleration of lift in upward direction a = 2 m/s²

⇒Let the weight shown by machine be N

⇒Then equation of motion for body :- ma = N-mg

i.e  N = m(a+g)

or N = 40(2+10) = 480

⇒Thus weight of the man recorded by machine = N/g = 480/10 = 48 Kg