A man is standing space station, which is orbiting carth at an altitude 520 km with a constant speed 7.6 km/s. If the man's weight is 50 kg, on an international his acceleration is
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Answer:
as we know that g'/g=(R/R+H)2 so here H= 520Km
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Explanation:
A man of mass is 50 standing on a international space station the diatance of station from centre of earth
r=R+H=6400+520
=6920
centripetal acceleration
a=v^2÷r
=(7.6×10^3)^2÷6920×10^3
=8.4ms^-2
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