Question

A man is three times as old as his son .five years
later, the man
shall be two and
half times old as his son , what is present age of son?
​

Answer 1

Answer:

the present age of the son is 15 years.

the present age of the father is 45 years

Step-by-step explanation:

Let the age of son be 'x' and that of his father be 'y'.

So according to the question, the 1st equation that can be formed will be:

son - x

father - 3x

Now after 5 years:

Age of son = (x+5)

Age of father = (y+5)

3x+5) = 2.5×(x+5)

=3x + 5 = 2.5x + 12.5

=3x - 2.5x - 12.5 - 5

=0.5x = 7.5

= 7.5/0.5

= 15

Thus, the present age of son is 15 years.

Thus, the present age of father is 45 years.[3*15]

Answer 2

Answer:

45 years

Step-by-step explanation:

Let the man's age be x years and his son's age be y years

According to given condition:  

x=3y .(i)

x+5= 5/2(y+5)  

2(x+5) = 5y+25  

2x+10= 5y+25  

2x = 5y+15

Substituting value from (i)

2(3y) = 5y+15  

6y =5y+15  

Y= 15 years  

Substituting value in (i)  

x= 3*15  

x= 45 years

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