Question

A man is thrice as old as his son after 12 years he will be twice as old as his son at that time find their present ages ​

Answer 1

Answer:

Let age of son = x

father's age = 3x

After 12 years

3x + 12 = 2 (x + k)

3x - 2x = 24 - 12

x = 12

Son age = x

= 12 years

Father's age = 3x

= 3 × 12 = 36 years

Answer 2

Answer:son=12

man=24

Step-by-step explanation:let the man age be 3 y

let the son be y        : son = 12 yrs

after 12 yrs                 man=36 yrs

man =3y + 12

son = y + 12

3y + 12=[y+12]2

3y + 12=2y+24

3y-2y=24-12

y=12