Question

a man is thrice as old as his son .five years ago the man was four times old as his son. find the present ages

Answer 1

Let x = age of the son
3x = age of the father
3x-5 = 4(x-5)
3x-5 = 4x -20
20-5 = 4x -3x
x = 15
3x = 3(15) = 45
The father is 45 years old.
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Answer 2

let the sons age be x
fathers age=3x
equation- 3x-5= 4(x-5)
  = 3x-5=4x-20
  = x=15 years
Sons age= 15 years
Fathers age = 15*3 = 45 years