Particles move in a straight line such that displacement s and time t is given by equation s= t³-6t²+3t+4. Find the velocity if acceleration is 0.
sreedhar2:
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hence velocity at acceleration is equal to zero is -9m/s
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Hmm.. Plz explain me a bit how you got there
we need to differentiate displacement twice to get acceleration,if we equate it to zero we get time . substitute it in velocity equation we gets the velocity
Ohhkk. I get it now.
Answered by
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Hey there !!!!!
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s=t³-6t²+3t+4
Differentiating distance covered gives velocity of the body. Further differentiation gives acceleration of the body.
s=t³-6t²+3t+4
Differentiating wrt to "t"
ds/dt = 3t²-12t+3---->Equation1
v=3t²-12t+3
Further differentiating equation 1
d²s/dt²= 6t-12
acceleration = 6t-12
According to question acceleration of the body is zero
6t-12=0
6t=12
t=2
v=3t²-12t+3
v= 3*(2)²-12*2+3
v= 12-24+3 = -9m/s
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Hope this helped you................
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
s=t³-6t²+3t+4
Differentiating distance covered gives velocity of the body. Further differentiation gives acceleration of the body.
s=t³-6t²+3t+4
Differentiating wrt to "t"
ds/dt = 3t²-12t+3---->Equation1
v=3t²-12t+3
Further differentiating equation 1
d²s/dt²= 6t-12
acceleration = 6t-12
According to question acceleration of the body is zero
6t-12=0
6t=12
t=2
v=3t²-12t+3
v= 3*(2)²-12*2+3
v= 12-24+3 = -9m/s
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Hope this helped you................
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