Math, asked by vadhijha036, 3 months ago

A man is thrice as old as his son five years ago the man was four times as old as his son. find their present ages ​

Answers

Answered by asahilthakur
1

Answer:

Let the present age of son be x.

Present age of man = 3x

Age of son 5 years ago = x-5

Age of man 5 years ago = 3x-5

According to Question,

4(x-5) = 3x-5

=> 4x-20 = 3x-5

=> 4x-3x = 20-5

=> x = 15

Hence, age of son = 15 years

Age of man = (3×15) years = 45 years

Answered by amareshjally46
0

Answer:

hope this will help you...

thanx

Attachments:
Similar questions