Question

a man is thrice as old as his son . Three years ago the man was four times as old as his son. Find their present ages. 

Answer 1

Answer:

Step-by-step explanation:

m=3n

m-3=4(n-3)

3n-3=4n-12

n=9

m=27

The man is 27. His son is 9..

Answer 2

Answer:

Step-by-step explanation:

Let the preset ages of the man and his son be "x " and "y" respectively.

as per the question,

x = 3y                                 -------> (1) 

ages five years ago,

age of father = x - 3

age of son = y - 3

so,

x - 3 = 4(y - 3)

x - 3 = 4y - 12

from equation (1) 

3y - 3 = 4y - 12

3y - 4y = -12+3

-y = -9

y = 9

x = 3y

x = 3*9

   = 27

Hence, present ages of father and son are :-

age of father = x = 27 years

age of son = y = 9 years