A man is thwice as old as his son. Five years ago the man was four times as old as his son. Find their present ages.
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A man is thrice as old as his son. Five years ago the man was four times as old as his son. Find their present ages.
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ANSWER
Let the present ages of the man and his son be "x " and "y" respectively.
As per the question,
x=3y -------> (1)
Ages five years ago,
age of father = x−5
age of son =y−5
So,
x−5=4(y−5)
x−5=4y−20
from equation (1)
3y−5=4y−20
4y−3y=−5+20
y=15
x=3y
x=3∗15=45
Hence, present ages of father and son are :-
age of father = x=45years
age of son = y=15years
Step-by-step explanation:
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Let the age of son be x
Let his father's age be 3x
Five years ago, age of son = x - 5
Five years ago, age of father = 3x - 5
5 years ago the man was four times as old as his son = 4(x - 5)
According to the question,
3x - 5 = 4(x - 5)
3x - 5 = 4x - 20
3x - 4x = -20 + 5
-x= -15
x = 15
Present age of son is x
=> 15 years
Present age of father =. 3x
=> 3 * 15
=> 45 years
∴ The age of son and his father is 15 years and 45 years respectively.