Math, asked by pradeepksahoo804, 5 months ago

A man is twice as fast as a woman and a woman is twice as fast as a boy. If all of them i. e. a man, a woman and boy can finish together in 4 days, in how many days a boy shall do it alone? ​

Answers

Answered by AADIT1902
0

Answer:

7 days

Step-by-step explanation:

Let the days in which. the boy can do the work be x.

Work done by boy in 1 day= 1/x

Work done by woman in 1 day= 1/2x

Work done by man in 1 day= 1/4x

Work done by all of them in one day= 1/4

Therefore, 1/x+1/2x+1/4x= 1/4

7/4x= 1/4

7= 1/4*4x

4x= 7*4

x= 7

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