Question

a man is twice as hold as his son. 20 years ago the age of the man was 12 times the age of the man was time the age of the son .find there present ages​

Answer 1

★ Appropriate question :

A man is twice as old as his son. 20 years ago the age of the man was 12 times the age of the son. Find their present ages.

Solution :

Let,

The present age of Son = x

The present age of Man = 2x

20 years ago,

The age of Son = x - 20

The age of Man = 2x - 20

Also,

The age of the man was 12 times the age of the son

So,

⇒ 12 (x - 20) = 2x - 20

⇒ 12x - 240 = 2x - 20

⇒ 12x - 2x = - 20 + 240

⇒ 10x = 220

⇒ x = 220 / 10

⇒ x = 22

The present age of Son = 22 years

The present age of Man = 2x

⇒ 2 (22)

⇒ 44

The present age of Man = 44 years

Therefore,

The present age of Son = 22 years

The present age of Man = 44 years

Answer 2

Answer:

Given :-

• A man is twice as old as his son. 20 years ago the age of the man was 12 times was the age of the son.

To Find :-

• What is their present ages.

Solution :-

» Let, the present age of the son be x

» And, the present age of man will be 2x

» 20 years ago the age of the man was 12 times of the age of the son.

According to the question,

⇒ (2x - 20) = 12(x - 20)

⇒ 2x - 20 = 12x - 240

⇒ 2x - 12x = - 240 + 20

⇒ - 10x = - 220

⇒ x = $\sf\dfrac{\cancel{- 220}}{\cancel{- 10}}$

➠ x = 22

Hence, the required ages are :

✦ Present age of son = x = 22 years

✦ Present age of man = 2x = 2(22) = 44 years

$\therefore$ The present age of son is 22 years and the present age of man is 44 years .