a man is twice as old as his son . 10 years ago the man was thrice as old as his son find their present ages
Answers
Answered by
1
let man be x
son be x/2
x-10 = 3(x/2-10)
x-10 = 3x/2 -30
20 = x/2
x= 40
man age is 40 yrs and son age is 20
son be x/2
x-10 = 3(x/2-10)
x-10 = 3x/2 -30
20 = x/2
x= 40
man age is 40 yrs and son age is 20
satyanarayan1:
your answer is wrong
answer is -20 and -40
friend age never comes in negative
have you understood friend
I have not given answer in negative
okk
I had given man=40 and friend=20
your answer is right
I mistake me
Answered by
1
let take son x
man is 2x
10 years ago=x-10 and 2x-10
2x-10=3 (x-10)
2x-10=3x-30
-10+30=3x-2x
20=x
man 20×2=40
man is 2x
10 years ago=x-10 and 2x-10
2x-10=3 (x-10)
2x-10=3x-30
-10+30=3x-2x
20=x
man 20×2=40
okkk
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