A man is twice as old as his son. 12 years ago the man was thrice as old as his son.find their present ages.
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let the age man be x& that of his son be y.
by the1st given condition
y=2x
2x-y=0................(1)
by the second given condition
y-12=3x
3x-y=-12................(2)
subtracting equation 1&2
2x-y-(3x-y) =0-(-12)
2x-y-3x+y=12
x=12
substitute x=12 in eqn(1)
2x-y=0
2(12)-y=o
24=y
y=24
SOLn:x=12, y=24
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by the1st given condition
y=2x
2x-y=0................(1)
by the second given condition
y-12=3x
3x-y=-12................(2)
subtracting equation 1&2
2x-y-(3x-y) =0-(-12)
2x-y-3x+y=12
x=12
substitute x=12 in eqn(1)
2x-y=0
2(12)-y=o
24=y
y=24
SOLn:x=12, y=24
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