Question

A man is twice as old as his son 20 years ago the age of the man was 12 times the age of his son find their present ages

Answer 1

Let son's age be x years
then,father's age=2x years
Before 20 years,son's age=x-20 years
And,father's age=2x-20 years
ATQ
12 (x-20)=2x-20
12x-240=2x-20
12x-2x=240-20
10x=220
x=22
Hence,present age of son=x=22 years
And,present age of father=2x=2×22=44 years

Answer 2

The present age of son is 22 years.

The present age of man is 44 years.

Step-by-step explanation:

Let the age of son is 'x' years.

Given:

• A man is twice as old as his son.

The age of man is '2x' years.

• 20 years ago the age of the man was 12 times the age of his son.

$\rightarrow \: 2x - 20 = 12 \times (x - 20) \\ \rightarrow \: 2x - 20 = 12x - 240 \\ \rightarrow \: 10x = 220 \\ \rightarrow \: x = 22 \: years$

The present age of son is 22 years.

The present age of son is 22 years.The present age of man is 44 years.