A man is twice as old as his son. 20 years ago, the age of the man was 12 times the age of the son. Find their present ages.
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Answers
Answered by
3
age of man 20 years ago = 12
so we will add to find present age =
12 + 20 = 32
and his son age is = 32 / 2 = 16
hope it help u
so we will add to find present age =
12 + 20 = 32
and his son age is = 32 / 2 = 16
hope it help u
Answered by
7
Father age = a
son = a/2
According to question
a - 20 = (a/2 -20)12
a -20 = 6a -240
5a = 220
a = 44
Father's age = 44
Son age = 44/2 =22
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