A man is twice as old as his son 20 years ago the age of the man was 12 times the age of the son find the present age
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present age of man=2× son's present age
x=2y
before 20 yrs..
x-20=12×(y-8)
x-20=12y-96
x-12y=-96+20
x-12y=-76
2y-12y=-76
-10y=-76
y=76/10
y=7.6
x=2×7.6
x=15.2..
x=2y
before 20 yrs..
x-20=12×(y-8)
x-20=12y-96
x-12y=-96+20
x-12y=-76
2y-12y=-76
-10y=-76
y=76/10
y=7.6
x=2×7.6
x=15.2..
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1
the present age is 32 years
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pls mark me brainliest
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