Question

A man is twice as old as his son 20years ago the age of the man was 12 times the ago of the son find their present age

Answer 1

Answer:

Let son's age be x years

then,father's age=2x years

Before 20 years,son's age=x-20 years

And,father's age=2x-20 years

ATQ

12 (x-20)=2x-20

12x-240=2x-20

12x-2x=240-20

10x=220

x=22

Hence,present age of son=x=22 years

And,present age of father=2x=2×22=44 years

Answer 2

Answer:4

Step-by-step explanation:

Let the age of the son be x

Before 20 years

(X-20)2= 12x

2x -40= 12x

10x=40

X=4

So age of son = 4 years