Question

A man is walking along the boundary of a rectangular Garden whose length and breadth is 18 and 65 respectively find the distance covered by him to take two rounds of it​

Answer 1

Answer:

kdshskshdsjsodjdfhrubdnndndm

shsshseidrb

djddhrhhrb

hdbejfjfj

jhfjoffbkfktfjfn

dbdnfifjifhfi

cfjffkfkkgkjgonkgnogjgogjgot

Answer 2

Answer:

$\large\boxed{\sf{332\:m}}$

Step-by-step explanation:

Given that a rectangular garden,

• Length, l = 65 m
• Breadth, b = 18 m

We know that,

• Perimeter, p = 2(l + b)

Therefore, We get,

$\sf{= > p = 2(65 + 18)} \\ \\ \sf{ = > p = 2 \times 83 }\\ \\ \sf{ = > p = 166 \: m}$

Perimeter is the distance covered in one round of the garden.

Therefore, Distance covered in two rounds will be two times of Perimeter.

$\sf{= > 2p = 2 \times 166 }\\ \\ \sf{ = > 2p = 332 \: m}$

Hence, he covered 332 m in two rounds.