A man is walking due west at 5 kmph. Rain appears to him to be falling vertically downwards at the rate of 5 kmph. Then true velocity of the rain fall is
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Velocity of rain with respect to the ground is 5√2 km /hr
Given-
- Speed of man due west = 5 kmph
- Rain falling vertically downwards with a speed of = 5 kmph
- Velocity of man with respect to ground is (Vmg) = 5 (-i) kmph
- Velocity of rain with respect to man (Vrm) = 5 (-j) kmph
Vrm = Vrg - Vmg
- 5 (j) = Vrg - (-5) (i)
Vrg = -5 j - 5 i
Magnitude of Vrg = { (-5)² + (-5)² }^1/2
Vrg = 5√2 km /hr
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