Physics, asked by noormahammad20pe61d9, 11 months ago

A man is walking on a road with velocity V. Velocity of rain relative to the
man appears to be 2 V and the rain is falling down vertically. Then actual
velocity of the rain is​

Answers

Answered by shailendrachoubay216
19

Actual velocity of the rain is​ \sqrt{3}\times V.

Explanation:

1. Velocity of man = V

2. Relative velocity of rain with respect to man = 2 V

3. Let actual velocity of rain = U

4. Where rain is falling vertically downward. So actual velocity of rain(U) is perpendicular to man velocity(V).

5. From Pythagoras

   (2V)^{2}= V^{2}+U^{2}

   4V^{2}= V^{2}+U^{2}

   U^{2}=3V^{2}

  So

   Actual velocity of rain U=\sqrt{3}\times V

 

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Answered by satyaswetha07
2

Answer: 3V

Explanation:

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