Question

A man is walking on a road with velocity V. Velocity of rain relative to the
man appears to be 2 V and the rain is falling down vertically. Then actual
velocity of the rain is​

Answer 1

Actual velocity of the rain is​ $\sqrt{3}\times V$.

Explanation:

1. Velocity of man = V

2. Relative velocity of rain with respect to man = 2 V

3. Let actual velocity of rain = U

4. Where rain is falling vertically downward. So actual velocity of rain(U) is perpendicular to man velocity(V).

5. From Pythagoras

   $(2V)^{2}= V^{2}+U^{2}$

   $4V^{2}= V^{2}+U^{2}$

   $U^{2}=3V^{2}$

  So

   Actual velocity of rain $U=\sqrt{3}\times V$

 

Answer 2

Answer: 3V

Explanation: