A man jogs 190 m in 48 sec and another 250 m in 62 sec .Find his average speed In km/hr.
Answers
Answered by
0
Average speed = total distance/total time
Total distance=190+250=440m
Total time=48+62=110sec
Ave. Speed = 440/11=4m/s
In km/h:
4m/s = 4/1000÷1/3600
=4*18/5
14.4km/h
Total distance=190+250=440m
Total time=48+62=110sec
Ave. Speed = 440/11=4m/s
In km/h:
4m/s = 4/1000÷1/3600
=4*18/5
14.4km/h
Answered by
1
average speed = total distance/total time
= 190+250/48+62
= 440/110
= 4m/s
= 4×18/5= 14.4km/sec
= 190+250/48+62
= 440/110
= 4m/s
= 4×18/5= 14.4km/sec
Similar questions