A man leaves a place at 6 a.m. on his bicycle moving at 8 km/hr. Another man
leaves the same place at 8 a.m. on his scooter, moving at 40 km/hr. At what
time does he overtake the man on the bicycle? (Imagine, both are moving in
the same route)
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Answer:
distance=2*8=16
time to overtake=16/(40-8)
=16/32
=1/2hour
= 30 minutes
he overtake 8:30 am
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