Question

an alloy weighlhing 72kgs contains elements A,B and C in population 1:2:3, weights of A,B and C will be ? ​

Answer 1

Let the numbers in ratio be x

A=x

B=2x

C=3x

A/q

x+2x+3x=72kg.

6x=72kg

x=72/6kg

=12kg

Therefore, A=12kg.

B=2×12kg.=24kg.

C=3×12 kg. = 36 kg.

Answer 2

Total weight of alloy = 72 kg ratio of ABC = ,1,2,3 = 1+2+3=6

weight of A =1/6×72=12kg

weight of B= 2/6×72=24 kg

weight of B=3/6×72=36kg. ans