a man leaves for a town 840 km away. on the first day, he completed 5/12 of the trip. he rested for the night and then continued on the remainder of the trip on the following day. 1) how many kn did the man travel of hr first day? 2) how many km does he have to travel on the second day? 3) on the second day, he left an average speed of 50 km/hr, at what time would he arrive at his destination?
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Answer:
1) man total trip in km = 840 km
5/12 of trip then = 840* 5/12= 350km
2) 840 - 350= 490 km
3) speed = distance/time
50 km/hr = 490 km/time
time = 490/50
= 9.8 hr
Step-by-step explanation:
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