Question

Monochromatic light of wavelength
400 nm and 560 nm are incident
simultaneously on double slits
apparatus whose slits separation is
0.1 mm and screen distance is 1 m.
Distance between areas of total
darkness will be

Answer 1

Answer:

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Answer 2

Explanation:

Its is Out of Box question

For first minima point

(2n - 1)400 = (2m -1)560  ------1

n/m = 7/5

2n - 1 = 7 and 2m -1 = 5

                n = 4 and m= 3

Getting second minimal position made by both

Multiply by 3 ( less number )

n/m = 21 / 15

2n - 1 = 21 and 2m -1 = 15

                n = 11 and m =8

Required distance = distance between 4th and 11th minima

By subtracting we get 28