Math, asked by brainliestanswer53, 10 months ago

a man leaves Rs 240000 to his three heirs Aslam, Pervaiz, and Sana. According to his will, it is to be distributed in the ratio of 5:4:3. how much of the inheritance does each heir receive?​

Answers

Answered by ansh2014chauhan
2

Hey mate ,

Let the common ratio be x

Thus the share of heirs Aslam , Pervaiz and Sana = 5x,4x,3x respectively .

Total money = Rs 2,40,000

Thus ,

5x+4x+3x = 240000

12x = 240000

x = 240000/12

x = 20,000

Thus ,

Share of heir Aslam = 5×20000= Rs 1,00,000

Of heir Pervaiz = 4×20000 = Rs 80,000

Of heir Sana = 3×20000 = Rs 60,000

Hope you find it helpful!!!

Do mark it as brainliest!!

Answered by niharikam54
5

Answer:

given total amount = 240000

ratio = 5 : 4 : 3

sum of the terms of the ratio = 5+4+3=12

inheritance received by aslam = 5/12 ×240000

Step-by-step explanation:

=100000

inheritance received by pervaiz = 4/12×240000

=80000

inheritance received by sana = 3 /12 × 240000

= 60000

hope this helps you .Mark me as BRAINLIEST if you got the correct answer

Similar questions