Math, asked by nirmaldey70, 1 year ago

A man left 25% of his money to his mother and 55% to his daughter and remaining rupees 9000 to his brother how much money did he leave and find the share of his mother and daughter.

Answers

Answered by kriti6997
27

Answer:

money recieved by the brother =9000

his percentage =100-(25+55)

100-80

=20%

=the number whose 20%is 9000

100/20×9000

45000

money recieved by mother =25/100×45000

11250

money recieved by his daughter = 55/100×45000

24750

Answered by welltododevon
12

Answer:

Total money man left is 45000 Rs

Mother's share is 45000 \times 0.25=11250

Daughter's share is 45000\times 0.55=24750

Step-by-step explanation:

Money left for his mother is 25%

Money left for his daughter is 55%

Remaining  money in terms of percentage is = 100-25-55= 20%

20% is equal to 9000.

Using cross multiplication , we can find the total money

20%---> 9000

100%-----> ?

=\frac{9000\times 100}{20}\\=45000

Total money man left is 45000 Rs

Mother's share is 45000 \times 0.25=11250

Daughter's share is 45000\times 0.55=24750

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