a man left 32% of his property to his wife 30%to his elder son 28%to his younger son and the rest to his daughter lf the daughter share is75000 find the valu of the mans property,thewife share,the total share of two sons.
Answers
Answered by
4
Given that daughter gets (100- 32-30-28)% of man's property. This implies that daughter gets only 10% of the property. 10%= 75000 (given)
10= (75000/ total man's property)*100. which implies that total man's property is 7,50,000. therefore wife's share is 2,40,000 elder son's property is 2,25,000 and younger son's property is 2,10,000. This we get by using the formula for %,
%=(individual's property/ total property) * 100
10= (75000/ total man's property)*100. which implies that total man's property is 7,50,000. therefore wife's share is 2,40,000 elder son's property is 2,25,000 and younger son's property is 2,10,000. This we get by using the formula for %,
%=(individual's property/ total property) * 100
Similar questions