Question

A man left inheritance to 3 sons, his 4 daughters and his wife. Each son received twice as much as his daughter. His wife received 600000,which was one quarter of the money. How much did each son get?

Answer 1

Answer:

Step-by-step explanation:

let the total inheritence be x

let the inheritence of the son be y

let the inheritence of daughter be z

1z = 2y

inheritence of wife 600000 which is 1/4 of the total inheritence

$\frac{1}{4}$x = 600000

x = 600000 ×4

  = 2400000

wifes inheritence = 600000

total inheritence = 2400000

left inheritence = 2400000-600000 = 180000

inheritence of 3 sons  + inheritence of 4 daughters = 1800000

z+z+z+y+y+y+y = 1800000

2y+2y+2y+y+y+y+y = 1800000

10y = 1800000

y = $\frac{1800000}{10}$

y = 180000

inheritence of each son = z = 2y = 2 ×180000 = 360000