Math, asked by sneha622, 1 year ago

a man left one third of his property for his son,one fourth for his daughter and the remaining for his wife. if the wife's share was rupees 32000,how much money did the man leave?

Answers

Answered by imthebest56
5
total share =x




sons share = x/3

daughter's share = x/4

share given till now = x/3 +x/4= 7x/12

share left for mother = x-7x/12 = 5x/12

given..
5x/12= 32000

solve to get x



imthebest56: let total share be x.... sons share+ daughter share= x/4 + x/3 = 7x/12..... share left for mother = 5x/12= 32000
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Answered by rajeev378
10
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Here is your answer.

Let Man has Total money is Rs x

His son has
 = \frac{1}{3} \times x \\ = \frac{x}{3}

His Daughter has
 = \frac{1}{4} \times x \\ = \frac{x}{4}
His Wife has
 = x - \frac{x}{3} - \frac{x}{4} \\ = \frac{12x - 4x - 3x}{12} \\ \\ = \frac{12x - 7x }{12} \\ = \frac{5x}{12}
ATQ
 \frac{5x}{12} = 32000 \\ 5x = 32000 \times 12 \\ x = \frac{32000 \times 12}{5} \\ x = 6400 \times 12 \\ x = 76800
Therefore Man has Rs 76,800

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