Question

A man lifts an LPG cylinder of mass 16kg to load on a truck of height 1.2m. What is the work done by the man to load such 55cylinders.​

Answer 1

Answer:

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Explanation:

Answer 2

Answer:

$\boxed{\huge{\pink{10348.8 \: joule}}}$

Explanation:

$\bold{ \underline{ \red{Given}}} \longrightarrow \\ mass \: of \: cylinder = 16 \: kg \\ height \: of \: truck = 1.2 \: m \\ number \: of \: cylinders = 55$

$\bold{ \underline{ \blue{Concept \: used}}} \longrightarrow \\ 1)weight \: of \: a \: body = m \: g \\ where \\ m = mass \: of \: body \\ g = gravitational \: acceleration \\ 2)work \: done = force \: \times displacement$

$\bold{ \underline{ \green{Solution}}} \longrightarrow \\ force \: applied \: on \: cylinder \: in \: \\ loading \: it \: in \: to \: truck \: is \: its \: weight \\ weight \: of \: one \: cylinder \: = mg \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 16 \times 9.8 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 156.8 \: newton \\ work \: done \: in \: loading \: a \: cylinder \\ = force \: \times displacement \\ = weight \: of \: cylinder \times height \: of \: truck \\ = 156.8 \times 1.2 \\ = 188.16 \: joule \\ work \: done \: in \: loading \: 55 \: cylinder \\= 55 \times 188.16 \\ = 10348.8 \: joule$