Question

A man loses 20 percent of his money after spending 25 percent of remainder he has left with rs. 480 how much money did he originally have

Answer 1

Let originally 100%
Remaining 80%.
25% of remaining =60%=480
10%=80
100%=800₹

Answer 2

Answer:

The answer is 800.

Step-by-step explanation:

Let a man have Rs.x.

Remainder money, after losses $20 \%$ of his money

$=x-20 \% \text$ of

$x=x-\frac{x \times 20}{10}$

Simplifying the equation,

$=\frac{5 x-x}{5}$

We get,

$=\frac{4 x}{5}$

Remainder money, after the spending $25 \%$of his

remainder money $=\frac{4 x}{5}-25 \% \text { of }\left(\frac{4 x}{5}\right)$

$&=\frac{4 x}{5}-\left(\frac{4 x}{5} \times \frac{25}{100}\right)$

$&=\frac{4 x}{5}-\frac{x}{5}$

Simplifying,

$=\frac{4 x-x}{5}$

We get,

$=\frac{3 x}{5}\end{aligned}$

According to the question,

$&\frac{3 x}{5}=480$

$&=x=\frac{480 \times 5}{3}=$

Rs.800.

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