Question

A man made a trip of 480 km/hr in 9 hrs . Some part of the trip was covered at 45km/hr and the remaining at 60km/hr . Find the part of the trip covered by him at 60km/hr.

Answer 1

$\sf\large{\underline{\underline{Given:}}}$

$\sf\large{ \: \: \: Total\:Distance\:of\:trip = 480\:km}$

$\sf\large{ \: \: \: Total\:Time\:of\:journey = 9\:Hrs}$

$\sf\large{Now,}$

$\sf\large{ \: \: \: Let\:'x'\:hrs\:be\:travel\:with\:45\:km\:per\:hr\:and}$$\sf\large{rest\:with\:60\:km\:per\:hr}$

$\sf\large{\underline{\underline{Solution:}}}$

$\sf\large{\red{\implies 15x + 60(9 - x) = 480}}$

$\sf\large{\purple{\implies 45x + 450 - 60x = 480}}$

$\sf\large{\orange{\implies 15x = 60}}$

$\sf\large{\green{\implies x = 4}}$

$\sf\large{\underline{\underline{Therefore,}}}$

$\sf\large{ \: \: \: Total\:Distance\:covered\:\:with\:60\:km\:per}$$\sf\large{ \: \: \: =60 × 5 = 300\:Km}$

Answer 2

Answer:

300km

Explanation:

Given :

• Distance of trip => 480km

• Time taken to complete journey => 9 hrs
• Some part of the trip covered at 45km/hr and remaining 60km/hr

To Find :

• The part of the trip covered by him at 60km/hr.

Solution :

Let 'x' hrs be travel with  45km/h and rest with  60km/h

$\Rightarrow$ 15 x + 60 ( 9 − x ) = 480

$\Rightarrow$ 45x + 450 − 60x = 480

$\Rightarrow$ 15x = 60

[ x = 4 ]

Therefore, Total distance covered with  60km/hr  = 60 × 5 = 300 km .